104113121311401 has 4 divisors (see below), whose sum is σ = 138817495081872. Its totient is φ = 69408747540932.

The previous prime is 104113121311379. The next prime is 104113121311439.

104113121311401 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104113121311401 - 2¹³ = 104113121303209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (104113121311481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17352186885231 + ... + 17352186885236.

It is an arithmetic number, because the mean of its divisors is an integer number (34704373770468).

Almost surely, 2^{104113121311401} is an apocalyptic number.

It is an amenable number.

104113121311401 is a deficient number, since it is larger than the sum of its proper divisors (34704373770471).

104113121311401 is an equidigital number, since it uses as much as digits as its factorization.

104113121311401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34704373770470.

The product of its (nonzero) digits is 288, while the sum is 24.

The spelling of 104113121311401 in words is "one hundred four trillion, one hundred thirteen billion, one hundred twenty-one million, three hundred eleven thousand, four hundred one".