10412040200313 has 4 divisors (see below), whose sum is σ = 13882720267088. Its totient is φ = 6941360133540.

The previous prime is 10412040200311. The next prime is 10412040200339. The reversal of 10412040200313 is 31300204021401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10412040200313 - 2¹ = 10412040200311 is a prime.

It is a super-2 number, since 2×10412040200313² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10412040200313.

It is not an unprimeable number, because it can be changed into a prime (10412040200311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1735340033383 + ... + 1735340033388.

It is an arithmetic number, because the mean of its divisors is an integer number (3470680066772).

Almost surely, 2^{10412040200313} is an apocalyptic number.

It is an amenable number.

10412040200313 is a deficient number, since it is larger than the sum of its proper divisors (3470680066775).

10412040200313 is an equidigital number, since it uses as much as digits as its factorization.

10412040200313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3470680066774.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 10412040200313 its reverse (31300204021401), we get a palindrome (41712244221714).

The spelling of 10412040200313 in words is "ten trillion, four hundred twelve billion, forty million, two hundred thousand, three hundred thirteen".