Base | Representation |
---|---|
bin | 11110010011011010000… |
… | …00110101111011111111 |
3 | 10200112112210020022101001 |
4 | 33021231000311323333 |
5 | 114024400010214403 |
6 | 2114154205431131 |
7 | 135140115445306 |
oct | 17115500657377 |
9 | 3615483208331 |
10 | 1041211023103 |
11 | 371636529579 |
12 | 14996356b4a7 |
13 | 77255201a04 |
14 | 385757b343d |
15 | 1c13e714c1d |
hex | f26d035eff |
1041211023103 has 2 divisors, whose sum is σ = 1041211023104. Its totient is φ = 1041211023102.
The previous prime is 1041211023079. The next prime is 1041211023113. The reversal of 1041211023103 is 3013201121401.
It is a strong prime.
It is an emirp because it is prime and its reverse (3013201121401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1041211023103 - 233 = 1032621088511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1041211023113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520605511551 + 520605511552.
It is an arithmetic number, because the mean of its divisors is an integer number (520605511552).
Almost surely, 21041211023103 is an apocalyptic number.
1041211023103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041211023103 is an equidigital number, since it uses as much as digits as its factorization.
1041211023103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1041211023103 its reverse (3013201121401), we get a palindrome (4054412144504).
The spelling of 1041211023103 in words is "one trillion, forty-one billion, two hundred eleven million, twenty-three thousand, one hundred three".
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