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10412112431401 is a prime number
BaseRepresentation
bin1001011110000100001001…
…0000110100100100101001
31100212101111000110220001121
42113201002100310210221
52331043001240301101
634051131452415241
72123151565251352
oct227410220644451
940771430426047
1010412112431401
11335483002a3aa
121201b2b477521
135a6b20005325
1427dd3dc18d29
15130c99dba0a1
hex97842434929

10412112431401 has 2 divisors, whose sum is σ = 10412112431402. Its totient is φ = 10412112431400.

The previous prime is 10412112431261. The next prime is 10412112431429. The reversal of 10412112431401 is 10413421121401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6154591914025 + 4257520517376 = 2480845^2 + 2063376^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10412112431401 is a prime.

It is not a weakly prime, because it can be changed into another prime (10412112491401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206056215700 + 5206056215701.

It is an arithmetic number, because the mean of its divisors is an integer number (5206056215701).

Almost surely, 210412112431401 is an apocalyptic number.

It is an amenable number.

10412112431401 is a deficient number, since it is larger than the sum of its proper divisors (1).

10412112431401 is an equidigital number, since it uses as much as digits as its factorization.

10412112431401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 10412112431401 its reverse (10413421121401), we get a palindrome (20825533552802).

The spelling of 10412112431401 in words is "ten trillion, four hundred twelve billion, one hundred twelve million, four hundred thirty-one thousand, four hundred one".