Base | Representation |
---|---|
bin | 10011011001001110… |
… | …11011011111010011 |
3 | 222212122102002010021 |
4 | 21230213123133103 |
5 | 132311011211011 |
6 | 4441105444311 |
7 | 516011216521 |
oct | 115447333723 |
9 | 28778362107 |
10 | 10412210131 |
11 | 446346a644 |
12 | 2027040697 |
13 | c9c2155ab |
14 | 70abc5311 |
15 | 40e184471 |
hex | 26c9db7d3 |
10412210131 has 2 divisors, whose sum is σ = 10412210132. Its totient is φ = 10412210130.
The previous prime is 10412210129. The next prime is 10412210153. The reversal of 10412210131 is 13101221401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10412210131 - 21 = 10412210129 is a prime.
It is a super-3 number, since 3×104122101313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 10412210129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10412210161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206105065 + 5206105066.
It is an arithmetic number, because the mean of its divisors is an integer number (5206105066).
Almost surely, 210412210131 is an apocalyptic number.
10412210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10412210131 is an equidigital number, since it uses as much as digits as its factorization.
10412210131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10412210131 its reverse (13101221401), we get a palindrome (23513431532).
The spelling of 10412210131 in words is "ten billion, four hundred twelve million, two hundred ten thousand, one hundred thirty-one".
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