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104123144224471 is a prime number
BaseRepresentation
bin10111101011001100001111…
…000001100011111011010111
3111122200002000221120222211111
4113223030033001203323113
5102121423144410140341
61005241302340515451
730634435402610101
oct2753141701437327
9448602027528744
10104123144224471
11301a4417480289
12b81791a3abb87
134613a02669398
141b9d830cc4571
15c087367b2681
hex5eb30f063ed7

104123144224471 has 2 divisors, whose sum is σ = 104123144224472. Its totient is φ = 104123144224470.

The previous prime is 104123144224349. The next prime is 104123144224507. The reversal of 104123144224471 is 174422441321401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104123144224471 - 213 = 104123144216279 is a prime.

It is a super-3 number, since 3×1041231442244713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104123144224871) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52061572112235 + 52061572112236.

It is an arithmetic number, because the mean of its divisors is an integer number (52061572112236).

Almost surely, 2104123144224471 is an apocalyptic number.

104123144224471 is a deficient number, since it is larger than the sum of its proper divisors (1).

104123144224471 is an equidigital number, since it uses as much as digits as its factorization.

104123144224471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172032, while the sum is 40.

Adding to 104123144224471 its reverse (174422441321401), we get a palindrome (278545585545872).

The spelling of 104123144224471 in words is "one hundred four trillion, one hundred twenty-three billion, one hundred forty-four million, two hundred twenty-four thousand, four hundred seventy-one".