Base | Representation |
---|---|
bin | 10111101011001100001111… |
… | …000001100011111011010111 |
3 | 111122200002000221120222211111 |
4 | 113223030033001203323113 |
5 | 102121423144410140341 |
6 | 1005241302340515451 |
7 | 30634435402610101 |
oct | 2753141701437327 |
9 | 448602027528744 |
10 | 104123144224471 |
11 | 301a4417480289 |
12 | b81791a3abb87 |
13 | 4613a02669398 |
14 | 1b9d830cc4571 |
15 | c087367b2681 |
hex | 5eb30f063ed7 |
104123144224471 has 2 divisors, whose sum is σ = 104123144224472. Its totient is φ = 104123144224470.
The previous prime is 104123144224349. The next prime is 104123144224507. The reversal of 104123144224471 is 174422441321401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 104123144224471 - 213 = 104123144216279 is a prime.
It is a super-3 number, since 3×1041231442244713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104123144224871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52061572112235 + 52061572112236.
It is an arithmetic number, because the mean of its divisors is an integer number (52061572112236).
Almost surely, 2104123144224471 is an apocalyptic number.
104123144224471 is a deficient number, since it is larger than the sum of its proper divisors (1).
104123144224471 is an equidigital number, since it uses as much as digits as its factorization.
104123144224471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172032, while the sum is 40.
Adding to 104123144224471 its reverse (174422441321401), we get a palindrome (278545585545872).
The spelling of 104123144224471 in words is "one hundred four trillion, one hundred twenty-three billion, one hundred forty-four million, two hundred twenty-four thousand, four hundred seventy-one".
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