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104130011140 = 2255206500557
BaseRepresentation
bin110000011111010100…
…0011110000000000100
3100221202222222122110021
41200332220132000010
53201224240324030
6115500415304524
710344303330211
oct1407650360004
9327688878407
10104130011140
1140185749651
1218220b1b144
139a86351a0c
14507b778b08
152a96ae197a
hex183ea1e004

104130011140 has 12 divisors (see below), whose sum is σ = 218673023436. Its totient is φ = 41652004448.

The previous prime is 104130011087. The next prime is 104130011171. The reversal of 104130011140 is 41110031401.

It can be written as a sum of positive squares in 2 ways, for example, as 46110690756 + 58019320384 = 214734^2 + 240872^2 .

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2603250259 + ... + 2603250298.

It is an arithmetic number, because the mean of its divisors is an integer number (18222751953).

Almost surely, 2104130011140 is an apocalyptic number.

104130011140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

104130011140 is an abundant number, since it is smaller than the sum of its proper divisors (114543012296).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

104130011140 is a wasteful number, since it uses less digits than its factorization.

104130011140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5206500566 (or 5206500564 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 104130011140 its reverse (41110031401), we get a palindrome (145240042541).

The spelling of 104130011140 in words is "one hundred four billion, one hundred thirty million, eleven thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 5206500557 10413001114 20826002228 26032502785 52065005570 104130011140