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10413049497353 is a prime number
BaseRepresentation
bin1001011110000111101000…
…0111011100011100001001
31100212110220022201202212222
42113201322013130130021
52331101411132403403
634051404445143425
72123214034215146
oct227417207343411
940773808652788
1010413049497353
113355170a78978
12120215125ab75
135a6c3c1a8c19
1427ddcc4633cd
15130d022b9338
hex9787a1dc709

10413049497353 has 2 divisors, whose sum is σ = 10413049497354. Its totient is φ = 10413049497352.

The previous prime is 10413049497269. The next prime is 10413049497359. The reversal of 10413049497353 is 35379494031401.

It is a happy number.

10413049497353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9174162516544 + 1238886980809 = 3028888^2 + 1113053^2 .

It is a cyclic number.

It is not a de Polignac number, because 10413049497353 - 224 = 10413032720137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10413049497295 and 10413049497304.

It is not a weakly prime, because it can be changed into another prime (10413049497359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206524748676 + 5206524748677.

It is an arithmetic number, because the mean of its divisors is an integer number (5206524748677).

Almost surely, 210413049497353 is an apocalyptic number.

It is an amenable number.

10413049497353 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413049497353 is an equidigital number, since it uses as much as digits as its factorization.

10413049497353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4898880, while the sum is 53.

The spelling of 10413049497353 in words is "ten trillion, four hundred thirteen billion, forty-nine million, four hundred ninety-seven thousand, three hundred fifty-three".