Base | Representation |
---|---|
bin | 1001011110000111101001… |
… | …1100100011011111011101 |
3 | 1100212110220201010220222112 |
4 | 2113201322130203133131 |
5 | 2331101414042000021 |
6 | 34051405203523405 |
7 | 2123214132234041 |
oct | 227417234433735 |
9 | 40773821126875 |
10 | 10413055031261 |
11 | 3355174108653 |
12 | 1202153089565 |
13 | 5a6c40395a1c |
14 | 27ddcd0a4021 |
15 | 130d02a0dd5b |
hex | 9787a7237dd |
10413055031261 has 2 divisors, whose sum is σ = 10413055031262. Its totient is φ = 10413055031260.
The previous prime is 10413055031257. The next prime is 10413055031311. The reversal of 10413055031261 is 16213055031401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9840204348100 + 572850683161 = 3136910^2 + 756869^2 .
It is a cyclic number.
It is not a de Polignac number, because 10413055031261 - 22 = 10413055031257 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10413055031251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206527515630 + 5206527515631.
It is an arithmetic number, because the mean of its divisors is an integer number (5206527515631).
Almost surely, 210413055031261 is an apocalyptic number.
It is an amenable number.
10413055031261 is a deficient number, since it is larger than the sum of its proper divisors (1).
10413055031261 is an equidigital number, since it uses as much as digits as its factorization.
10413055031261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
The spelling of 10413055031261 in words is "ten trillion, four hundred thirteen billion, fifty-five million, thirty-one thousand, two hundred sixty-one".
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