Base | Representation |
---|---|
bin | 1001011110000111110100… |
… | …1001010100100100010100 |
3 | 1100212111000212100212212220 |
4 | 2113201331021110210110 |
5 | 2331102012140233134 |
6 | 34051413502342340 |
7 | 2123215222213161 |
oct | 227417511244424 |
9 | 40774025325786 |
10 | 10413100321044 |
11 | 3355197731523 |
12 | 120216628a9b0 |
13 | 5a6c49892205 |
14 | 27ddd50d3068 |
15 | 130d069a8149 |
hex | 9787d254914 |
10413100321044 has 24 divisors (see below), whose sum is σ = 24953916085728. Its totient is φ = 3377221725600.
The previous prime is 10413100321033. The next prime is 10413100321087. The reversal of 10413100321044 is 44012300131401.
It is a super-4 number, since 4×104131003210444 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11726463882 + ... + 11726464769.
It is an arithmetic number, because the mean of its divisors is an integer number (1039746503572).
Almost surely, 210413100321044 is an apocalyptic number.
It is an amenable number.
10413100321044 is an abundant number, since it is smaller than the sum of its proper divisors (14540815764684).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10413100321044 is a wasteful number, since it uses less digits than its factorization.
10413100321044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23452928695 (or 23452928693 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 10413100321044 its reverse (44012300131401), we get a palindrome (54425400452445).
The spelling of 10413100321044 in words is "ten trillion, four hundred thirteen billion, one hundred million, three hundred twenty-one thousand, forty-four".
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