1041310050433 has 8 divisors (see below), whose sum is σ = 1045386121320. Its totient is φ = 1037238956160.

The previous prime is 1041310050383. The next prime is 1041310050439. The reversal of 1041310050433 is 3340500131401.

It can be written as a sum of positive squares in 4 ways, for example, as 331894666609 + 709415383824 = 576103^2 + 842268^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1041310050433 - 2⁹ = 1041310049921 is a prime.

It is a super-2 number, since 2×1041310050433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1041310050398 and 1041310050407.

It is not an unprimeable number, because it can be changed into a prime (1041310050439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 824578 + ... + 1662091.

It is an arithmetic number, because the mean of its divisors is an integer number (130673265165).

Almost surely, 2^{1041310050433} is an apocalyptic number.

It is an amenable number.

1041310050433 is a deficient number, since it is larger than the sum of its proper divisors (4076070887).

1041310050433 is a wasteful number, since it uses less digits than its factorization.

1041310050433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2488307.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1041310050433 its reverse (3340500131401), we get a palindrome (4381810181834).

The spelling of 1041310050433 in words is "one trillion, forty-one billion, three hundred ten million, fifty thousand, four hundred thirty-three".