1041312131401 has 4 divisors (see below), whose sum is σ = 1041314400000. Its totient is φ = 1041309862804.

The previous prime is 1041312131399. The next prime is 1041312131417.

1041312131401 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1041312131401 - 2¹ = 1041312131399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1041312132401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175801 + ... + 1453798.

It is an arithmetic number, because the mean of its divisors is an integer number (260328600000).

Almost surely, 2^{1041312131401} is an apocalyptic number.

It is an amenable number.

1041312131401 is a deficient number, since it is larger than the sum of its proper divisors (2268599).

1041312131401 is an equidigital number, since it uses as much as digits as its factorization.

1041312131401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2268598.

The product of its (nonzero) digits is 288, while the sum is 22.

The spelling of 1041312131401 in words is "one trillion, forty-one billion, three hundred twelve million, one hundred thirty-one thousand, four hundred one".