Base | Representation |
---|---|
bin | 10111101011010101100111… |
… | …000100000111100001001111 |
3 | 111122201001000112102120020012 |
4 | 113223111213010013201033 |
5 | 102122104304033133033 |
6 | 1005250045315343435 |
7 | 30635243022651263 |
oct | 2753254704074117 |
9 | 448631015376205 |
10 | 104133211224143 |
11 | 301a8712a97122 |
12 | b8198698b1b7b |
13 | 46149481b481a |
14 | 1ba0107cc80a3 |
15 | c08b254a7248 |
hex | 5eb56710784f |
104133211224143 has 2 divisors, whose sum is σ = 104133211224144. Its totient is φ = 104133211224142.
The previous prime is 104133211224127. The next prime is 104133211224227. The reversal of 104133211224143 is 341422112331401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104133211224143 - 24 = 104133211224127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104133211224103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52066605612071 + 52066605612072.
It is an arithmetic number, because the mean of its divisors is an integer number (52066605612072).
Almost surely, 2104133211224143 is an apocalyptic number.
104133211224143 is a deficient number, since it is larger than the sum of its proper divisors (1).
104133211224143 is an equidigital number, since it uses as much as digits as its factorization.
104133211224143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 104133211224143 its reverse (341422112331401), we get a palindrome (445555323555544).
The spelling of 104133211224143 in words is "one hundred four trillion, one hundred thirty-three billion, two hundred eleven million, two hundred twenty-four thousand, one hundred forty-three".
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