10413322444113 has 4 divisors (see below), whose sum is σ = 13884429925488. Its totient is φ = 6942214962740.

The previous prime is 10413322444111. The next prime is 10413322444153. The reversal of 10413322444113 is 31144422331401.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10413322444113 - 2¹ = 10413322444111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10413322444111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1735553740683 + ... + 1735553740688.

It is an arithmetic number, because the mean of its divisors is an integer number (3471107481372).

Almost surely, 2^{10413322444113} is an apocalyptic number.

It is an amenable number.

10413322444113 is a deficient number, since it is larger than the sum of its proper divisors (3471107481375).

10413322444113 is an equidigital number, since it uses as much as digits as its factorization.

10413322444113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3471107481374.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 10413322444113 its reverse (31144422331401), we get a palindrome (41557744775514).

The spelling of 10413322444113 in words is "ten trillion, four hundred thirteen billion, three hundred twenty-two million, four hundred forty-four thousand, one hundred thirteen".