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1041341000243 is a prime number
BaseRepresentation
bin11110010011101001100…
…00101010101000110011
310200112212211210211111012
433021310300222220303
5114030131244001433
62114215131341135
7135143254312355
oct17116460525063
93615784724435
101041341000243
113716a29352a5
1214999abb17ab
137727610cc6b
1438588b690d5
151c14ad3b848
hexf274c2aa33

1041341000243 has 2 divisors, whose sum is σ = 1041341000244. Its totient is φ = 1041341000242.

The previous prime is 1041341000131. The next prime is 1041341000309. The reversal of 1041341000243 is 3420001431401.

1041341000243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (3420001431401) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1041341000243 is a prime.

It is not a weakly prime, because it can be changed into another prime (1041341000443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520670500121 + 520670500122.

It is an arithmetic number, because the mean of its divisors is an integer number (520670500122).

Almost surely, 21041341000243 is an apocalyptic number.

1041341000243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041341000243 is an equidigital number, since it uses as much as digits as its factorization.

1041341000243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1041341000243 its reverse (3420001431401), we get a palindrome (4461342431644).

The spelling of 1041341000243 in words is "one trillion, forty-one billion, three hundred forty-one million, two hundred forty-three", and thus it is an aban number.