Base | Representation |
---|---|
bin | 1001011110001001000110… |
… | …0010101111111100100111 |
3 | 1100212111220201021221211211 |
4 | 2113202101202233330213 |
5 | 2331103212241443421 |
6 | 34051511445212251 |
7 | 2123226546024154 |
oct | 227422142577447 |
9 | 40774821257754 |
10 | 10413442531111 |
11 | 3355352915a64 |
12 | 1202240a01087 |
13 | 5a6ca274b789 |
14 | 28002873322b |
15 | 130d26a539e1 |
hex | 978918aff27 |
10413442531111 has 2 divisors, whose sum is σ = 10413442531112. Its totient is φ = 10413442531110.
The previous prime is 10413442531049. The next prime is 10413442531127. The reversal of 10413442531111 is 11113524431401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10413442531111 - 213 = 10413442522919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10413442531181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206721265555 + 5206721265556.
It is an arithmetic number, because the mean of its divisors is an integer number (5206721265556).
Almost surely, 210413442531111 is an apocalyptic number.
10413442531111 is a deficient number, since it is larger than the sum of its proper divisors (1).
10413442531111 is an equidigital number, since it uses as much as digits as its factorization.
10413442531111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 10413442531111 its reverse (11113524431401), we get a palindrome (21526966962512).
The spelling of 10413442531111 in words is "ten trillion, four hundred thirteen billion, four hundred forty-two million, five hundred thirty-one thousand, one hundred eleven".
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