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104140231121 is a prime number
BaseRepresentation
bin110000011111100111…
…1011101000111010001
3100221210201012212122002
41200333033131013101
53201234344343441
6115501422323345
710344456234113
oct1407717350721
9327721185562
10104140231121
114019049a013
1218224429555
139a884bc744
14507cc793b3
152a9795eb9b
hex183f3dd1d1

104140231121 has 2 divisors, whose sum is σ = 104140231122. Its totient is φ = 104140231120.

The previous prime is 104140231109. The next prime is 104140231123. The reversal of 104140231121 is 121132041401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103530141121 + 610090000 = 321761^2 + 24700^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-104140231121 is a prime.

Together with 104140231123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 104140231093 and 104140231102.

It is not a weakly prime, because it can be changed into another prime (104140231123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52070115560 + 52070115561.

It is an arithmetic number, because the mean of its divisors is an integer number (52070115561).

Almost surely, 2104140231121 is an apocalyptic number.

It is an amenable number.

104140231121 is a deficient number, since it is larger than the sum of its proper divisors (1).

104140231121 is an equidigital number, since it uses as much as digits as its factorization.

104140231121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 104140231121 its reverse (121132041401), we get a palindrome (225272272522).

The spelling of 104140231121 in words is "one hundred four billion, one hundred forty million, two hundred thirty-one thousand, one hundred twenty-one".