Base | Representation |
---|---|
bin | 110000011111111100… |
… | …1000001111111000011 |
3 | 100221211110201121011011 |
4 | 1200333321001333003 |
5 | 3201300142130201 |
6 | 115502452101351 |
7 | 10344650666323 |
oct | 1407771017703 |
9 | 327743647134 |
10 | 104151130051 |
11 | 401966635a1 |
12 | 18228004857 |
13 | 9a8a837507 |
14 | 50804b5283 |
15 | 2a988b4151 |
hex | 183fe41fc3 |
104151130051 has 2 divisors, whose sum is σ = 104151130052. Its totient is φ = 104151130050.
The previous prime is 104151130049. The next prime is 104151130067. The reversal of 104151130051 is 150031151401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104151130051 - 21 = 104151130049 is a prime.
Together with 104151130049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (104151100051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52075565025 + 52075565026.
It is an arithmetic number, because the mean of its divisors is an integer number (52075565026).
Almost surely, 2104151130051 is an apocalyptic number.
104151130051 is a deficient number, since it is larger than the sum of its proper divisors (1).
104151130051 is an equidigital number, since it uses as much as digits as its factorization.
104151130051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 104151130051 its reverse (150031151401), we get a palindrome (254182281452).
The spelling of 104151130051 in words is "one hundred four billion, one hundred fifty-one million, one hundred thirty thousand, fifty-one".
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