Base | Representation |
---|---|
bin | 10111101011100110011110… |
… | …000110000101010101010101 |
3 | 111122202202202011122220221021 |
4 | 113223212132012011111111 |
5 | 102122403342433334131 |
6 | 1005302241524321141 |
7 | 30636453443020105 |
oct | 2753463606052525 |
9 | 448682664586837 |
10 | 104151314355541 |
11 | 30205362809742 |
12 | b8212805431b1 |
13 | 46165718b3cab |
14 | 1ba0d442bd205 |
15 | c09334932e11 |
hex | 5eb99e185555 |
104151314355541 has 2 divisors, whose sum is σ = 104151314355542. Its totient is φ = 104151314355540.
The previous prime is 104151314355481. The next prime is 104151314355553. The reversal of 104151314355541 is 145553413151401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86144200332100 + 18007114023441 = 9281390^2 + 4243479^2 .
It is a cyclic number.
It is not a de Polignac number, because 104151314355541 - 213 = 104151314347349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104151314352541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52075657177770 + 52075657177771.
It is an arithmetic number, because the mean of its divisors is an integer number (52075657177771).
Almost surely, 2104151314355541 is an apocalyptic number.
It is an amenable number.
104151314355541 is a deficient number, since it is larger than the sum of its proper divisors (1).
104151314355541 is an equidigital number, since it uses as much as digits as its factorization.
104151314355541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360000, while the sum is 43.
The spelling of 104151314355541 in words is "one hundred four trillion, one hundred fifty-one billion, three hundred fourteen million, three hundred fifty-five thousand, five hundred forty-one".
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