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10420130113 = 37927493747
BaseRepresentation
bin10011011010001011…
…01001000101000001
3222220012022110021221
421231011221011001
5132320023130423
64441551315041
7516135434041
oct115505510501
928805273257
1010420130113
114467989a88
12202981ba81
13ca0a59483
1470bc87721
1540ebeae5d
hex26d169141

10420130113 has 4 divisors (see below), whose sum is σ = 10447624240. Its totient is φ = 10392635988.

The previous prime is 10420130107. The next prime is 10420130117. The reversal of 10420130113 is 31103102401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10420130113 is a prime.

It is a super-2 number, since 2×104201301132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10420130117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13746495 + ... + 13747252.

It is an arithmetic number, because the mean of its divisors is an integer number (2611906060).

Almost surely, 210420130113 is an apocalyptic number.

It is an amenable number.

10420130113 is a deficient number, since it is larger than the sum of its proper divisors (27494127).

10420130113 is an equidigital number, since it uses as much as digits as its factorization.

10420130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27494126.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10420130113 its reverse (31103102401), we get a palindrome (41523232514).

The spelling of 10420130113 in words is "ten billion, four hundred twenty million, one hundred thirty thousand, one hundred thirteen".

Divisors: 1 379 27493747 10420130113