Base | Representation |
---|---|
bin | 1001011110101001011001… |
… | …0110101110110011000011 |
3 | 1100220100021222200122100111 |
4 | 2113222112112232303003 |
5 | 2331223441434420342 |
6 | 34055504103532151 |
7 | 2123654452351141 |
oct | 227522626566303 |
9 | 40810258618314 |
10 | 10422113201347 |
11 | 3358aa221a931 |
12 | 1203a6075a057 |
13 | 5a7a54c02093 |
14 | 28060c0dc591 |
15 | 131182d7b217 |
hex | 97a965aecc3 |
10422113201347 has 2 divisors, whose sum is σ = 10422113201348. Its totient is φ = 10422113201346.
The previous prime is 10422113201341. The next prime is 10422113201399. The reversal of 10422113201347 is 74310231122401.
It is a weak prime.
It is an emirp because it is prime and its reverse (74310231122401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10422113201347 - 223 = 10422104812739 is a prime.
It is a super-2 number, since 2×104221132013472 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10422113201341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211056600673 + 5211056600674.
It is an arithmetic number, because the mean of its divisors is an integer number (5211056600674).
Almost surely, 210422113201347 is an apocalyptic number.
10422113201347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10422113201347 is an equidigital number, since it uses as much as digits as its factorization.
10422113201347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 10422113201347 its reverse (74310231122401), we get a palindrome (84732344323748).
The spelling of 10422113201347 in words is "ten trillion, four hundred twenty-two billion, one hundred thirteen million, two hundred one thousand, three hundred forty-seven".
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