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10422113201341 is a prime number
BaseRepresentation
bin1001011110101001011001…
…0110101110110010111101
31100220100021222200122100021
42113222112112232302331
52331223441434420331
634055504103532141
72123654452351132
oct227522626566275
940810258618307
1010422113201341
113358aa221a926
121203a6075a051
135a7a54c0208a
1428060c0dc589
15131182d7b211
hex97a965aecbd

10422113201341 has 2 divisors, whose sum is σ = 10422113201342. Its totient is φ = 10422113201340.

The previous prime is 10422113201299. The next prime is 10422113201347. The reversal of 10422113201341 is 14310231122401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8505120653316 + 1916992548025 = 2916354^2 + 1384555^2 .

It is an emirp because it is prime and its reverse (14310231122401) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10422113201341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10422113201347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211056600670 + 5211056600671.

It is an arithmetic number, because the mean of its divisors is an integer number (5211056600671).

Almost surely, 210422113201341 is an apocalyptic number.

It is an amenable number.

10422113201341 is a deficient number, since it is larger than the sum of its proper divisors (1).

10422113201341 is an equidigital number, since it uses as much as digits as its factorization.

10422113201341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10422113201341 its reverse (14310231122401), we get a palindrome (24732344323742).

The spelling of 10422113201341 in words is "ten trillion, four hundred twenty-two billion, one hundred thirteen million, two hundred one thousand, three hundred forty-one".