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10422413401331 is a prime number
BaseRepresentation
bin1001011110101010100000…
…1111111001110011110011
31100220101001220120101022102
42113222220033321303303
52331230100312320311
634055553550131015
72123665056122561
oct227525017716363
940811056511272
1010422413401331
113359136720598
121203b251b0a6b
135a7aa216cbc9
14280639d24a31
1513119e3c943b
hex97aa83f9cf3

10422413401331 has 2 divisors, whose sum is σ = 10422413401332. Its totient is φ = 10422413401330.

The previous prime is 10422413401289. The next prime is 10422413401333. The reversal of 10422413401331 is 13310431422401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10422413401331 - 226 = 10422346292467 is a prime.

It is a super-2 number, since 2×104224134013312 (a number of 27 digits) contains 22 as substring.

Together with 10422413401333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10422413401294 and 10422413401303.

It is not a weakly prime, because it can be changed into another prime (10422413401333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211206700665 + 5211206700666.

It is an arithmetic number, because the mean of its divisors is an integer number (5211206700666).

Almost surely, 210422413401331 is an apocalyptic number.

10422413401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

10422413401331 is an equidigital number, since it uses as much as digits as its factorization.

10422413401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 10422413401331 its reverse (13310431422401), we get a palindrome (23732844823732).

The spelling of 10422413401331 in words is "ten trillion, four hundred twenty-two billion, four hundred thirteen million, four hundred one thousand, three hundred thirty-one".