Base | Representation |
---|---|
bin | 10011011010100010… |
… | …11001000111000001 |
3 | 222220102002221200212 |
4 | 21231101121013001 |
5 | 132321320213213 |
6 | 4442141323505 |
7 | 516203553416 |
oct | 115521310701 |
9 | 28812087625 |
10 | 10423210433 |
11 | 44696a32a9 |
12 | 202a866595 |
13 | ca159754c |
14 | 70c44a10d |
15 | 4101089a8 |
hex | 26d4591c1 |
10423210433 has 2 divisors, whose sum is σ = 10423210434. Its totient is φ = 10423210432.
The previous prime is 10423210417. The next prime is 10423210453. The reversal of 10423210433 is 33401232401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7972168369 + 2451042064 = 89287^2 + 49508^2 .
It is an emirp because it is prime and its reverse (33401232401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10423210433 - 24 = 10423210417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10423210399 and 10423210408.
It is not a weakly prime, because it can be changed into another prime (10423210453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211605216 + 5211605217.
It is an arithmetic number, because the mean of its divisors is an integer number (5211605217).
Almost surely, 210423210433 is an apocalyptic number.
It is an amenable number.
10423210433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10423210433 is an equidigital number, since it uses as much as digits as its factorization.
10423210433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 10423210433 its reverse (33401232401), we get a palindrome (43824442834).
The spelling of 10423210433 in words is "ten billion, four hundred twenty-three million, two hundred ten thousand, four hundred thirty-three".
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