Base | Representation |
---|---|
bin | 10011011010100011… |
… | …10111001000111001 |
3 | 222220102100012102102 |
4 | 21231101313020321 |
5 | 132321333132213 |
6 | 4442144113145 |
7 | 516204605132 |
oct | 115521671071 |
9 | 28812305372 |
10 | 10423333433 |
11 | 4469777757 |
12 | 202a9057b5 |
13 | ca160b526 |
14 | 70c47cc89 |
15 | 410130158 |
hex | 26d477239 |
10423333433 has 4 divisors (see below), whose sum is σ = 10423586448. Its totient is φ = 10423080420.
The previous prime is 10423333411. The next prime is 10423333469. The reversal of 10423333433 is 33433332401.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10423333433 - 212 = 10423329337 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10423333396 and 10423333405.
It is not an unprimeable number, because it can be changed into a prime (10423333493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48803 + ... + 152408.
It is an arithmetic number, because the mean of its divisors is an integer number (2605896612).
Almost surely, 210423333433 is an apocalyptic number.
It is an amenable number.
10423333433 is a deficient number, since it is larger than the sum of its proper divisors (253015).
10423333433 is an equidigital number, since it uses as much as digits as its factorization.
10423333433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 253014.
The product of its (nonzero) digits is 23328, while the sum is 29.
Adding to 10423333433 its reverse (33433332401), we get a palindrome (43856665834).
The spelling of 10423333433 in words is "ten billion, four hundred twenty-three million, three hundred thirty-three thousand, four hundred thirty-three".
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