Search a number
-
+
10423333433 = 51803201211
BaseRepresentation
bin10011011010100011…
…10111001000111001
3222220102100012102102
421231101313020321
5132321333132213
64442144113145
7516204605132
oct115521671071
928812305372
1010423333433
114469777757
12202a9057b5
13ca160b526
1470c47cc89
15410130158
hex26d477239

10423333433 has 4 divisors (see below), whose sum is σ = 10423586448. Its totient is φ = 10423080420.

The previous prime is 10423333411. The next prime is 10423333469. The reversal of 10423333433 is 33433332401.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10423333433 - 212 = 10423329337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10423333396 and 10423333405.

It is not an unprimeable number, because it can be changed into a prime (10423333493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48803 + ... + 152408.

It is an arithmetic number, because the mean of its divisors is an integer number (2605896612).

Almost surely, 210423333433 is an apocalyptic number.

It is an amenable number.

10423333433 is a deficient number, since it is larger than the sum of its proper divisors (253015).

10423333433 is an equidigital number, since it uses as much as digits as its factorization.

10423333433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 253014.

The product of its (nonzero) digits is 23328, while the sum is 29.

Adding to 10423333433 its reverse (33433332401), we get a palindrome (43856665834).

The spelling of 10423333433 in words is "ten billion, four hundred twenty-three million, three hundred thirty-three thousand, four hundred thirty-three".

Divisors: 1 51803 201211 10423333433