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10423441433 is a prime number
BaseRepresentation
bin10011011010100100…
…10001100000011001
3222220102112200120102
421231102101200121
5132321400111213
64442150305145
7516205535036
oct115522214031
928812480512
1010423441433
114469840909
12202a9581b5
13ca1648732
1470c4aa38d
15410152158
hex26d491819

10423441433 has 2 divisors, whose sum is σ = 10423441434. Its totient is φ = 10423441432.

The previous prime is 10423441411. The next prime is 10423441453. The reversal of 10423441433 is 33414432401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8214159424 + 2209282009 = 90632^2 + 47003^2 .

It is a cyclic number.

It is not a de Polignac number, because 10423441433 - 210 = 10423440409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10423441396 and 10423441405.

It is not a weakly prime, because it can be changed into another prime (10423441453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5211720716 + 5211720717.

It is an arithmetic number, because the mean of its divisors is an integer number (5211720717).

Almost surely, 210423441433 is an apocalyptic number.

It is an amenable number.

10423441433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10423441433 is an equidigital number, since it uses as much as digits as its factorization.

10423441433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 10423441433 its reverse (33414432401), we get a palindrome (43837873834).

The spelling of 10423441433 in words is "ten billion, four hundred twenty-three million, four hundred forty-one thousand, four hundred thirty-three".