10424341117 has 2 divisors, whose sum is σ = 10424341118. Its totient is φ = 10424341116.

The previous prime is 10424341087. The next prime is 10424341121. The reversal of 10424341117 is 71114342401.

10424341117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10142302681 + 282038436 = 100709^2 + 16794^2 .

It is an emirp because it is prime and its reverse (71114342401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10424341117 - 2¹¹ = 10424339069 is a prime.

It is a super-3 number, since 3×10424341117³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10424341217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5212170558 + 5212170559.

It is an arithmetic number, because the mean of its divisors is an integer number (5212170559).

Almost surely, 2^10424341117 is an apocalyptic number.

It is an amenable number.

10424341117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10424341117 is an equidigital number, since it uses as much as digits as its factorization.

10424341117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 28.

Adding to 10424341117 its reverse (71114342401), we get a palindrome (81538683518).

It can be divided in two parts, 10424 and 341117, that added together give a triangular number (351541 = T₈₃₈).

The spelling of 10424341117 in words is "ten billion, four hundred twenty-four million, three hundred forty-one thousand, one hundred seventeen".