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1043035402513 = 1380233492501
BaseRepresentation
bin11110010110110011100…
…00010011000100010001
310200201020221010101102211
433023121300103010101
5114042114030340023
62115055220312121
7135233250431566
oct17133160230421
93621227111384
101043035402513
11372392324855
1214a192542641
1377486179660
14386a9bd486d
151c1e9986a0d
hexf2d9c13111

1043035402513 has 4 divisors (see below), whose sum is σ = 1123268895028. Its totient is φ = 962801910000.

The previous prime is 1043035402511. The next prime is 1043035402523. The reversal of 1043035402513 is 3152045303401.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 427339378944 + 615696023569 = 653712^2 + 784663^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043035402513 - 21 = 1043035402511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1043035402511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40116746238 + ... + 40116746263.

It is an arithmetic number, because the mean of its divisors is an integer number (280817223757).

Almost surely, 21043035402513 is an apocalyptic number.

1043035402513 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1043035402513 is a deficient number, since it is larger than the sum of its proper divisors (80233492515).

1043035402513 is an equidigital number, since it uses as much as digits as its factorization.

1043035402513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80233492514.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 1043035402513 in words is "one trillion, forty-three billion, thirty-five million, four hundred two thousand, five hundred thirteen".

Divisors: 1 13 80233492501 1043035402513