Base | Representation |
---|---|
bin | 1001011111001110010110… |
… | …1100000101100001100001 |
3 | 1100221021220101200020121210 |
4 | 2113303211230011201201 |
5 | 2331404301214242423 |
6 | 34104224343540333 |
7 | 2124455350033314 |
oct | 227634554054141 |
9 | 40837811606553 |
10 | 10432034134113 |
11 | 3362223340519 |
12 | 120596b15a6a9 |
13 | 5a89763c78b7 |
14 | 280cad95c97b |
15 | 131563d1bb93 |
hex | 97ce5b05861 |
10432034134113 has 8 divisors (see below), whose sum is σ = 13910636860128. Its totient is φ = 6954060415424.
The previous prime is 10432034134073. The next prime is 10432034134127. The reversal of 10432034134113 is 31143143023401.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10432034134113 - 29 = 10432034133601 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (10432034134133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 157213131 + ... + 157279472.
It is an arithmetic number, because the mean of its divisors is an integer number (1738829607516).
Almost surely, 210432034134113 is an apocalyptic number.
It is an amenable number.
10432034134113 is a deficient number, since it is larger than the sum of its proper divisors (3478602726015).
10432034134113 is a wasteful number, since it uses less digits than its factorization.
10432034134113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 314503663.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 10432034134113 its reverse (31143143023401), we get a palindrome (41575177157514).
The spelling of 10432034134113 in words is "ten trillion, four hundred thirty-two billion, thirty-four million, one hundred thirty-four thousand, one hundred thirteen".
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