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10433121412255 = 542192101123539
BaseRepresentation
bin1001011111010010011001…
…1111101110010010011111
31100221101201011120200211121
42113310212133232102133
52331414013040143010
634104524304031411
72124524321532403
oct227644637562237
940841634520747
1010433121412255
1133627310566a3
121206013302567
135a8aba742b49
14280d74109103
151315c94dd3da
hex97d267ee49f

10433121412255 has 16 divisors (see below), whose sum is σ = 12523841193600. Its totient is φ = 8343767187360.

The previous prime is 10433121412247. The next prime is 10433121412321. The reversal of 10433121412255 is 55221412133401.

It is not a de Polignac number, because 10433121412255 - 23 = 10433121412247 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10433121412255.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 443215276 + ... + 443238814.

It is an arithmetic number, because the mean of its divisors is an integer number (782740074600).

Almost surely, 210433121412255 is an apocalyptic number.

10433121412255 is a deficient number, since it is larger than the sum of its proper divisors (2090719781345).

10433121412255 is a wasteful number, since it uses less digits than its factorization.

10433121412255 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48774.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 10433121412255 its reverse (55221412133401), we get a palindrome (65654533545656).

The spelling of 10433121412255 in words is "ten trillion, four hundred thirty-three billion, one hundred twenty-one million, four hundred twelve thousand, two hundred fifty-five".

Divisors: 1 5 4219 21011 21095 23539 105055 117695 88645409 99311041 443227045 494577929 496555205 2472889645 2086624282451 10433121412255