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10433241334249 is a prime number
BaseRepresentation
bin1001011111010010110110…
…1001001100000111101001
31100221102000112020100212221
42113310231221030013221
52331414234240143444
634104544230234041
72124530306050246
oct227645551140751
940842015210787
1010433241334249
113362792814888
1212060474b5921
135a8b095403c6
14280d860045cd
151315d4ccaa84
hex97d2da4c1e9

10433241334249 has 2 divisors, whose sum is σ = 10433241334250. Its totient is φ = 10433241334248.

The previous prime is 10433241334213. The next prime is 10433241334273. The reversal of 10433241334249 is 94243314233401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9543156640000 + 890084694249 = 3089200^2 + 943443^2 .

It is a cyclic number.

It is not a de Polignac number, because 10433241334249 - 29 = 10433241333737 is a prime.

It is not a weakly prime, because it can be changed into another prime (10433241332249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5216620667124 + 5216620667125.

It is an arithmetic number, because the mean of its divisors is an integer number (5216620667125).

Almost surely, 210433241334249 is an apocalyptic number.

It is an amenable number.

10433241334249 is a deficient number, since it is larger than the sum of its proper divisors (1).

10433241334249 is an equidigital number, since it uses as much as digits as its factorization.

10433241334249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 746496, while the sum is 43.

The spelling of 10433241334249 in words is "ten trillion, four hundred thirty-three billion, two hundred forty-one million, three hundred thirty-four thousand, two hundred forty-nine".