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1043412131317 is a prime number
BaseRepresentation
bin11110010111100000011…
…01011001110111110101
310200202020012000012012111
433023300031121313311
5114043402001200232
62115200435051021
7135245503531363
oct17136015316765
93622205005174
101043412131317
11372565a45776
1214a278740a71
13775162308ca
1438703c5c633
151c21caa0047
hexf2f0359df5

1043412131317 has 2 divisors, whose sum is σ = 1043412131318. Its totient is φ = 1043412131316.

The previous prime is 1043412131309. The next prime is 1043412131339. The reversal of 1043412131317 is 7131312143401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 917331035076 + 126081096241 = 957774^2 + 355079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1043412131317 - 23 = 1043412131309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1043412131387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 521706065658 + 521706065659.

It is an arithmetic number, because the mean of its divisors is an integer number (521706065659).

Almost surely, 21043412131317 is an apocalyptic number.

It is an amenable number.

1043412131317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1043412131317 is an equidigital number, since it uses as much as digits as its factorization.

1043412131317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1043412131317 its reverse (7131312143401), we get a palindrome (8174724274718).

The spelling of 1043412131317 in words is "one trillion, forty-three billion, four hundred twelve million, one hundred thirty-one thousand, three hundred seventeen".