Base | Representation |
---|---|
bin | 11110010111101100100… |
… | …11010001000001010111 |
3 | 10200202111022022111010012 |
4 | 33023312103101001113 |
5 | 114044104132044343 |
6 | 2115214525350435 |
7 | 135251154315320 |
oct | 17136623210127 |
9 | 3622438274105 |
10 | 1043514331223 |
11 | 3726086aa001 |
12 | 14a2a6a0841b |
13 | 77531464820 |
14 | 38713663447 |
15 | 1c226a3b718 |
hex | f2f64d1057 |
1043514331223 has 16 divisors (see below), whose sum is σ = 1284463143936. Its totient is φ = 825549118560.
The previous prime is 1043514331217. The next prime is 1043514331241. The reversal of 1043514331223 is 3221334153401.
It is a cyclic number.
It is not a de Polignac number, because 1043514331223 - 232 = 1039219363927 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1043514331223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1043514331243) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244040 + ... + 1465122.
It is an arithmetic number, because the mean of its divisors is an integer number (80278946496).
Almost surely, 21043514331223 is an apocalyptic number.
1043514331223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1043514331223 is a deficient number, since it is larger than the sum of its proper divisors (240948812713).
1043514331223 is a wasteful number, since it uses less digits than its factorization.
1043514331223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1230494.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 1043514331223 its reverse (3221334153401), we get a palindrome (4264848484624).
The spelling of 1043514331223 in words is "one trillion, forty-three billion, five hundred fourteen million, three hundred thirty-one thousand, two hundred twenty-three".
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