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104403140131 = 259134028987
BaseRepresentation
bin110000100111011101…
…0010111111000100011
3100222111000221000222211
41201032322113320203
53202304200441011
6115543453342551
710354131022513
oct1411672277043
9328430830884
10104403140131
114030593a494
1218298497a57
139acab01ac4
1450a5b55843
152ab0a93b21
hex184ee97e23

104403140131 has 4 divisors (see below), whose sum is σ = 104407195032. Its totient is φ = 104399085232.

The previous prime is 104403140113. The next prime is 104403140159. The reversal of 104403140131 is 131041304401.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 104403140131 - 211 = 104403138083 is a prime.

It is a super-2 number, since 2×1044031401312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104403180131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1988581 + ... + 2040406.

It is an arithmetic number, because the mean of its divisors is an integer number (26101798758).

Almost surely, 2104403140131 is an apocalyptic number.

104403140131 is a deficient number, since it is larger than the sum of its proper divisors (4054901).

104403140131 is an equidigital number, since it uses as much as digits as its factorization.

104403140131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4054900.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 104403140131 its reverse (131041304401), we get a palindrome (235444444532).

The spelling of 104403140131 in words is "one hundred four billion, four hundred three million, one hundred forty thousand, one hundred thirty-one".

Divisors: 1 25913 4028987 104403140131