10441123323131 has 2 divisors, whose sum is σ = 10441123323132. Its totient is φ = 10441123323130.

The previous prime is 10441123323109. The next prime is 10441123323133. The reversal of 10441123323131 is 13132332114401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10441123323131 - 2¹⁸ = 10441123060987 is a prime.

It is a super-3 number, since 3×10441123323131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 10441123323133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10441123323094 and 10441123323103.

It is not a weakly prime, because it can be changed into another prime (10441123323133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5220561661565 + 5220561661566.

It is an arithmetic number, because the mean of its divisors is an integer number (5220561661566).

Almost surely, 2^{10441123323131} is an apocalyptic number.

10441123323131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10441123323131 is an equidigital number, since it uses as much as digits as its factorization.

10441123323131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 10441123323131 its reverse (13132332114401), we get a palindrome (23573455437532).

The spelling of 10441123323131 in words is "ten trillion, four hundred forty-one billion, one hundred twenty-three million, three hundred twenty-three thousand, one hundred thirty-one".