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104435254025213 is a prime number
BaseRepresentation
bin10111101111101110111010…
…001101111101101111111101
3111200202220122102020122020012
4113233232322031331233331
5102142031400012301323
61010040520545033005
730666124644261116
oct2757567215755775
9450686572218205
10104435254025213
1130304819304071
12b868303325765
1346372822c5257
141bb099c46720d
15c11902180678
hex5efbba37dbfd

104435254025213 has 2 divisors, whose sum is σ = 104435254025214. Its totient is φ = 104435254025212.

The previous prime is 104435254025203. The next prime is 104435254025227. The reversal of 104435254025213 is 312520452534401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68596377337849 + 35838876687364 = 8282293^2 + 5986558^2 .

It is an emirp because it is prime and its reverse (312520452534401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104435254025213 - 228 = 104434985589757 is a prime.

It is a super-3 number, since 3×1044352540252133 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (104435254025203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52217627012606 + 52217627012607.

It is an arithmetic number, because the mean of its divisors is an integer number (52217627012607).

Almost surely, 2104435254025213 is an apocalyptic number.

It is an amenable number.

104435254025213 is a deficient number, since it is larger than the sum of its proper divisors (1).

104435254025213 is an equidigital number, since it uses as much as digits as its factorization.

104435254025213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576000, while the sum is 41.

The spelling of 104435254025213 in words is "one hundred four trillion, four hundred thirty-five billion, two hundred fifty-four million, twenty-five thousand, two hundred thirteen".