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104443410131 is a prime number
BaseRepresentation
bin110000101000101001…
…1111111011011010011
3100222120211200222001022
41201101103333123103
53202400003111011
6115551452430055
710355130223664
oct1412123773323
9328524628038
10104443410131
1140326644985
12182a9a7832b
139b062614c8
1450ab23936b
152ab439a8db
hex18514ff6d3

104443410131 has 2 divisors, whose sum is σ = 104443410132. Its totient is φ = 104443410130.

The previous prime is 104443410109. The next prime is 104443410179. The reversal of 104443410131 is 131014344401.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-104443410131 is a prime.

It is a super-2 number, since 2×1044434101312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 104443410131.

It is not a weakly prime, because it can be changed into another prime (104443413131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52221705065 + 52221705066.

It is an arithmetic number, because the mean of its divisors is an integer number (52221705066).

Almost surely, 2104443410131 is an apocalyptic number.

104443410131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104443410131 is an equidigital number, since it uses as much as digits as its factorization.

104443410131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 104443410131 its reverse (131014344401), we get a palindrome (235457754532).

The spelling of 104443410131 in words is "one hundred four billion, four hundred forty-three million, four hundred ten thousand, one hundred thirty-one".