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104521253055 = 3541169953257
BaseRepresentation
bin110000101010111110…
…0111100000010111111
3100222210021011210110120
41201111330330002333
53203024420044210
6120003313110023
710360063664202
oct1412574740277
9328707153416
10104521253055
114036658247a
121830bb58313
139b19417acb
1450b76dd939
152abb125270
hex1855f3c0bf

104521253055 has 16 divisors (see below), whose sum is σ = 171312884064. Its totient is φ = 54385041920.

The previous prime is 104521253021. The next prime is 104521253063. The reversal of 104521253055 is 550352125401.

It is not a de Polignac number, because 104521253055 - 29 = 104521252543 is a prime.

It is a super-3 number, since 3×1045212530553 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 84976014 + ... + 84977243.

It is an arithmetic number, because the mean of its divisors is an integer number (10707055254).

Almost surely, 2104521253055 is an apocalyptic number.

104521253055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

104521253055 is a deficient number, since it is larger than the sum of its proper divisors (66791631009).

104521253055 is a wasteful number, since it uses less digits than its factorization.

104521253055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169953306.

The product of its (nonzero) digits is 30000, while the sum is 33.

Adding to 104521253055 its reverse (550352125401), we get a palindrome (654873378456).

The spelling of 104521253055 in words is "one hundred four billion, five hundred twenty-one million, two hundred fifty-three thousand, fifty-five".

Divisors: 1 3 5 15 41 123 205 615 169953257 509859771 849766285 2549298855 6968083537 20904250611 34840417685 104521253055