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10472340477 = 33490780159
BaseRepresentation
bin10011100000011001…
…10011101111111101
31000000211120000110010
421300030303233331
5132421404343402
64451054333433
7520341265614
oct116014635775
930024500403
1010472340477
1144943aa445
1220431ba279
13cab809991
14714b9887b
154145b0a6c
hex270333bfd

10472340477 has 4 divisors (see below), whose sum is σ = 13963120640. Its totient is φ = 6981560316.

The previous prime is 10472340451. The next prime is 10472340479. The reversal of 10472340477 is 77404327401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10472340477 - 26 = 10472340413 is a prime.

It is a super-3 number, since 3×104723404773 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10472340479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1745390077 + ... + 1745390082.

It is an arithmetic number, because the mean of its divisors is an integer number (3490780160).

Almost surely, 210472340477 is an apocalyptic number.

It is an amenable number.

10472340477 is a deficient number, since it is larger than the sum of its proper divisors (3490780163).

10472340477 is an equidigital number, since it uses as much as digits as its factorization.

10472340477 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3490780162.

The product of its (nonzero) digits is 131712, while the sum is 39.

Adding to 10472340477 its reverse (77404327401), we get a palindrome (87876667878).

The spelling of 10472340477 in words is "ten billion, four hundred seventy-two million, three hundred forty thousand, four hundred seventy-seven".

Divisors: 1 3 3490780159 10472340477