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1049055913 is a prime number
BaseRepresentation
bin111110100001110…
…101001010101001
32201002222120011201
4332201311022221
54122024242123
6252032524201
734665554023
oct7641651251
92632876151
101049055913
1149918a264
122533b0661
13139454959
149d47b013
15621715ad
hex3e8752a9

1049055913 has 2 divisors, whose sum is σ = 1049055914. Its totient is φ = 1049055912.

The previous prime is 1049055893. The next prime is 1049055923. The reversal of 1049055913 is 3195509401.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1023168169 + 25887744 = 31987^2 + 5088^2 .

It is a cyclic number.

It is not a de Polignac number, because 1049055913 - 29 = 1049055401 is a prime.

It is a super-2 number, since 2×10490559132 = 2201036617200527138, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1049055923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 524527956 + 524527957.

It is an arithmetic number, because the mean of its divisors is an integer number (524527957).

Almost surely, 21049055913 is an apocalyptic number.

It is an amenable number.

1049055913 is a deficient number, since it is larger than the sum of its proper divisors (1).

1049055913 is an equidigital number, since it uses as much as digits as its factorization.

1049055913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24300, while the sum is 37.

The square root of 1049055913 is about 32389.1326373523. The cubic root of 1049055913 is about 1016.0916411568.

The spelling of 1049055913 in words is "one billion, forty-nine million, fifty-five thousand, nine hundred thirteen".