104933131 has 2 divisors, whose sum is σ = 104933132. Its totient is φ = 104933130.

The previous prime is 104933123. The next prime is 104933137. The reversal of 104933131 is 131339401.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 104933131 - 2³ = 104933123 is a prime.

It is a super-2 number, since 2×104933131² = 22021923962926322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 104933096 and 104933105.

It is not a weakly prime, because it can be changed into another prime (104933137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52466565 + 52466566.

It is an arithmetic number, because the mean of its divisors is an integer number (52466566).

Almost surely, 2^104933131 is an apocalyptic number.

104933131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104933131 is an equidigital number, since it uses as much as digits as its factorization.

104933131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

The square root of 104933131 is about 10243.6873732070. The cubic root of 104933131 is about 471.6692283584.

The spelling of 104933131 in words is "one hundred four million, nine hundred thirty-three thousand, one hundred thirty-one".