Base | Representation |
---|---|
bin | 110000110111010101… |
… | …1001101011000111111 |
3 | 101000212011122221120021 |
4 | 1201232223031120333 |
5 | 3204402111122103 |
6 | 120112411233011 |
7 | 10403261405506 |
oct | 1415653153077 |
9 | 330764587507 |
10 | 104936035903 |
11 | 40559724a16 |
12 | 18406a48767 |
13 | 9b84333c4a |
14 | 511683183d |
15 | 2ae2758bbd |
hex | 186eacd63f |
104936035903 has 2 divisors, whose sum is σ = 104936035904. Its totient is φ = 104936035902.
The previous prime is 104936035859. The next prime is 104936035907. The reversal of 104936035903 is 309530639401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 104936035903 - 213 = 104936027711 is a prime.
It is a super-2 number, since 2×1049360359032 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 104936035903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (104936035907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52468017951 + 52468017952.
It is an arithmetic number, because the mean of its divisors is an integer number (52468017952).
Almost surely, 2104936035903 is an apocalyptic number.
104936035903 is a deficient number, since it is larger than the sum of its proper divisors (1).
104936035903 is an equidigital number, since it uses as much as digits as its factorization.
104936035903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262440, while the sum is 43.
The spelling of 104936035903 in words is "one hundred four billion, nine hundred thirty-six million, thirty-five thousand, nine hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •