1050031000313 has 2 divisors, whose sum is σ = 1050031000314. Its totient is φ = 1050031000312.

The previous prime is 1050031000301. The next prime is 1050031000433. The reversal of 1050031000313 is 3130001300501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 975219451024 + 74811549289 = 987532^2 + 273517^2 .

It is a cyclic number.

It is not a de Polignac number, because 1050031000313 - 2⁴ = 1050031000297 is a prime.

It is a super-3 number, since 3×1050031000313³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1050031000291 and 1050031000300.

It is not a weakly prime, because it can be changed into another prime (1050031000013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525015500156 + 525015500157.

It is an arithmetic number, because the mean of its divisors is an integer number (525015500157).

Almost surely, 2^{1050031000313} is an apocalyptic number.

It is an amenable number.

1050031000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050031000313 is an equidigital number, since it uses as much as digits as its factorization.

1050031000313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 17.

Adding to 1050031000313 its reverse (3130001300501), we get a palindrome (4180032300814).

The spelling of 1050031000313 in words is "one trillion, fifty billion, thirty-one million, three hundred thirteen", and thus it is an aban number.