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10501000051 = 47223425533
BaseRepresentation
bin10011100011110100…
…01000101101110011
31000002211111001222211
421301322020231303
5133001224000201
64454000512551
7521140012333
oct116172105563
930084431884
1010501000051
1144a95a4843
12205091b757
13cb47327c9
147188d90c3
15416d72651
hex271e88b73

10501000051 has 4 divisors (see below), whose sum is σ = 10724425632. Its totient is φ = 10277574472.

The previous prime is 10501000049. The next prime is 10501000063. The reversal of 10501000051 is 15000010501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10501000051 - 21 = 10501000049 is a prime.

It is a super-2 number, since 2×105010000512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10500999995 and 10501000040.

It is not an unprimeable number, because it can be changed into a prime (10501000751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111712720 + ... + 111712813.

It is an arithmetic number, because the mean of its divisors is an integer number (2681106408).

Almost surely, 210501000051 is an apocalyptic number.

10501000051 is a deficient number, since it is larger than the sum of its proper divisors (223425581).

10501000051 is an equidigital number, since it uses as much as digits as its factorization.

10501000051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 223425580.

The product of its (nonzero) digits is 25, while the sum is 13.

Adding to 10501000051 its reverse (15000010501), we get a palindrome (25501010552).

The spelling of 10501000051 in words is "ten billion, five hundred one million, fifty-one", and thus it is an aban number.

Divisors: 1 47 223425533 10501000051