Base | Representation |
---|---|
bin | 110000111001100110… |
… | …0000001101111011001 |
3 | 101001001110010111202122 |
4 | 1201303030001233121 |
5 | 3210031001412201 |
6 | 120124114111025 |
7 | 10405201062062 |
oct | 1416314015731 |
9 | 331043114678 |
10 | 105011747801 |
11 | 40598437434 |
12 | 1842827b475 |
13 | 9b96c2259c |
14 | 51228dd569 |
15 | 2ae9211e1b |
hex | 1873301bd9 |
105011747801 has 2 divisors, whose sum is σ = 105011747802. Its totient is φ = 105011747800.
The previous prime is 105011747759. The next prime is 105011747803. The reversal of 105011747801 is 108747110501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86156338576 + 18855409225 = 293524^2 + 137315^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-105011747801 is a prime.
It is a super-2 number, since 2×1050117478012 (a number of 23 digits) contains 22 as substring.
Together with 105011747803, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (105011747803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52505873900 + 52505873901.
It is an arithmetic number, because the mean of its divisors is an integer number (52505873901).
Almost surely, 2105011747801 is an apocalyptic number.
It is an amenable number.
105011747801 is a deficient number, since it is larger than the sum of its proper divisors (1).
105011747801 is an equidigital number, since it uses as much as digits as its factorization.
105011747801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7840, while the sum is 35.
The spelling of 105011747801 in words is "one hundred five billion, eleven million, seven hundred forty-seven thousand, eight hundred one".
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