10501261333 has 2 divisors, whose sum is σ = 10501261334. Its totient is φ = 10501261332.

The previous prime is 10501261313. The next prime is 10501261423. The reversal of 10501261333 is 33316210501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10119957604 + 381303729 = 100598^2 + 19527^2 .

It is a cyclic number.

It is not a de Polignac number, because 10501261333 - 2¹⁷ = 10501130261 is a prime.

It is a super-2 number, since 2×10501261333² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10501261298 and 10501261307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10501261313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5250630666 + 5250630667.

It is an arithmetic number, because the mean of its divisors is an integer number (5250630667).

Almost surely, 2^10501261333 is an apocalyptic number.

It is an amenable number.

10501261333 is a deficient number, since it is larger than the sum of its proper divisors (1).

10501261333 is an equidigital number, since it uses as much as digits as its factorization.

10501261333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 10501261333 its reverse (33316210501), we get a palindrome (43817471834).

The spelling of 10501261333 in words is "ten billion, five hundred one million, two hundred sixty-one thousand, three hundred thirty-three".