105014111 has 2 divisors, whose sum is σ = 105014112. Its totient is φ = 105014110.

The previous prime is 105014099. The next prime is 105014131. The reversal of 105014111 is 111410501.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-105014111 is a prime.

It is a super-2 number, since 2×105014111² = 22055927018240642, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105014131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52507055 + 52507056.

It is an arithmetic number, because the mean of its divisors is an integer number (52507056).

Almost surely, 2^105014111 is an apocalyptic number.

105014111 is a deficient number, since it is larger than the sum of its proper divisors (1).

105014111 is an equidigital number, since it uses as much as digits as its factorization.

105014111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 14.

The square root of 105014111 is about 10247.6392891241. The cubic root of 105014111 is about 471.7905308563.

Adding to 105014111 its reverse (111410501), we get a palindrome (216424612).

The spelling of 105014111 in words is "one hundred five million, fourteen thousand, one hundred eleven".