1050313001 has 2 divisors, whose sum is σ = 1050313002. Its totient is φ = 1050313000.

The previous prime is 1050312983. The next prime is 1050313003. The reversal of 1050313001 is 1003130501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008697600 + 41615401 = 31760^2 + 6451^2 .

It is a cyclic number.

It is not a de Polignac number, because 1050313001 - 2¹⁴ = 1050296617 is a prime.

It is a super-2 number, since 2×1050313001² = 2206314800139252002, which contains 22 as substring.

Together with 1050313003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1050313003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525156500 + 525156501.

It is an arithmetic number, because the mean of its divisors is an integer number (525156501).

Almost surely, 2^1050313001 is an apocalyptic number.

It is an amenable number.

1050313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050313001 is an equidigital number, since it uses as much as digits as its factorization.

1050313001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

The square root of 1050313001 is about 32408.5328424475. The cubic root of 1050313001 is about 1016.4973414085.

Adding to 1050313001 its reverse (1003130501), we get a palindrome (2053443502).

The spelling of 1050313001 in words is "one billion, fifty million, three hundred thirteen thousand, one".