Base | Representation |
---|---|
bin | 11110100100011000100… |
… | …00010010011001100011 |
3 | 10201102001221222101122111 |
4 | 33102030100102121203 |
5 | 114202031211201011 |
6 | 2122302424020151 |
7 | 135612015021406 |
oct | 17221420223143 |
9 | 3642057871574 |
10 | 1050325100131 |
11 | 37549315653a |
12 | 14b687901657 |
13 | 780784b3cb8 |
14 | 38b9c001d3d |
15 | 1c4c4927121 |
hex | f48c412663 |
1050325100131 has 2 divisors, whose sum is σ = 1050325100132. Its totient is φ = 1050325100130.
The previous prime is 1050325100029. The next prime is 1050325100161. The reversal of 1050325100131 is 1310015230501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1050325100131 - 27 = 1050325100003 is a prime.
It is a super-2 number, since 2×10503251001312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1050325100161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525162550065 + 525162550066.
It is an arithmetic number, because the mean of its divisors is an integer number (525162550066).
Almost surely, 21050325100131 is an apocalyptic number.
1050325100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1050325100131 is an equidigital number, since it uses as much as digits as its factorization.
1050325100131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 450, while the sum is 22.
The spelling of 1050325100131 in words is "one trillion, fifty billion, three hundred twenty-five million, one hundred thousand, one hundred thirty-one".
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