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105033115 = 5113161603
BaseRepresentation
bin1100100001010…
…10110110011011
321022122020100101
412100222312123
5203342024430
614231120231
72413523665
oct620526633
9238566311
10105033115
1154319a30
122b213077
13189b6695
14dd41535
15934adca
hex642ad9b

105033115 has 16 divisors (see below), whose sum is σ = 141935616. Its totient is φ = 73922400.

The previous prime is 105033113. The next prime is 105033143. The reversal of 105033115 is 511330501.

It is not a de Polignac number, because 105033115 - 21 = 105033113 is a prime.

It is a super-2 number, since 2×1050331152 = 22063910493206450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 105033092 and 105033101.

It is not an unprimeable number, because it can be changed into a prime (105033113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29097 + ... + 32506.

It is an arithmetic number, because the mean of its divisors is an integer number (8870976).

Almost surely, 2105033115 is an apocalyptic number.

105033115 is a deficient number, since it is larger than the sum of its proper divisors (36902501).

105033115 is a wasteful number, since it uses less digits than its factorization.

105033115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61650.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 105033115 is about 10248.5664851237. The cubic root of 105033115 is about 471.8189885127.

Adding to 105033115 its reverse (511330501), we get a palindrome (616363616).

The spelling of 105033115 in words is "one hundred five million, thirty-three thousand, one hundred fifteen".

Divisors: 1 5 11 31 55 155 341 1705 61603 308015 677633 1909693 3388165 9548465 21006623 105033115